a car start moving from rest and covers a distance of 3km with a acceleration of 2m per min per sec. find the the total time taken and velocity at 3km
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Answer:
Maximum velocity attained is 20 metres/second
Total distance travelled is 500 metres
Initial speed (U) = 0
Acceleration (A) = 2
Time (T) = 10
Final speed (V) = U + AT
= 0 + 10 x 2
= 20
Hence maximum velocity attained is 20 m/s
Deceleration (D) = -1
Initial velocity after 20 seconds = V = 20
Final velocity (V1) = 0
Time (T1) = (V1 - U) / D
= (0 - 20) / (-1)
= 20 seconds
Total distance travelled = Distance while accelerating + Distance while decelerating + Distance without acceleration
= (0.5 x 2 x 10^2) + (20^2 / 2 x 1) + (20 x 10)
= 100 + 200 + 200
= 500 metres
Explanation:
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