Question

A car start moving from rest with a constant acceleration of 5 m/s2 along a straight line.Find the distance tarvel by it in 2nd second

Answer 1

Answer:

The distance travelled by the car in 2 second is 10 metre.

Explanation:

$\textbf{Given: }$

Initial velocity or u = 0

Acceleration or a = 5 m/s²

Time of journey or t = 2 seconds

$\textbf{ To Find : }$

Distance travelled or S = ?

$\textbf{Solution : }$

S = ut + ½ at²

$\textbf{Calculation: }$

S = ut + ½ at²

→ S = 0 × 2 + ½ × 5 × 2²

→ S = 0 + ½ × 5 × 4

→ S = 5 × 2

→ S = 10 m

To know:

initial velocity or u

initial velocity or u final velocity or v

initial velocity or u final velocity or v acceleration or a

initial velocity or u final velocity or v acceleration or a time of journey or t

and distance travelled or S.

Other equations of motion :

v = u + at

S = ut + ½ at²

v² = u² + 2aS

Answer 2

$\large\underline{\underline{\mathcal{\color{blue}ANSWER:}}}$

$\underline{\sf{Given:-}}$

• $\small\rm{Car\; is\; started\; from}$

$\;\;\;\;\;\;\;\;\rm{ rest \; that \; means \; initial \;velocity (u) = 0 m/s}$

• $\small\rm{Acceleration ( a ) = 5m/s^2}$

$\underline{\sf{To \;find:-}}$

• $\small\rm{Distance\; travelled\; at\; 2s}$

$\underline{\sf{Solution:-}}$

$\rm{Using \;the\; kinematic\; equation }: \\\bigstar\rm{s = ut+\dfrac{1}{2}at^2 }$

$\longrightarrow s = 0(2) + \dfrac{1}{2}(5)(2)^2 \\\\ \longrightarrow s = 5 \times 2 \\ \\ \dagger\boxed{\bf{\color{green}Distance (s) = 10m}}$