Question

A car start with an initial velocity of 4 metre per second is accelerated at 2 metre per second square find the velocity of the car after 10 second​

Answer 1

Answer:

The velocity of the car after 10 seconds is 24 m/s.

Step-by-step explanation:

Given:

Intial velocity of the car = 4 m/s

Acceleration of the car = 2 m/s²

To find:

Velocity of the car in 10 seconds

Solution :

We have -

• u = 4 m/s
• a = 2 m/s²
• t = 10 secs.
• v = ??

Equation of motion used : v = u + at

$\sf{\longrightarrow} \: v = 4 + (2)(10)$

$\sf{\longrightarrow} \: v =4 + 20$

$\sf{\longrightarrow} \: v =24$

Velocity = 24 m/s

The velocity of the car after 10 seconds = 24 m/s

Therefore, the velocity of the car after 10 seconds is 24 m/s.

Answer 2

Answer:

Given :-

• A car starts with an initial velocity of 4 m/s is accelerated at 2 m/s².

To Find :-

• What is the velocity of the car after 10 second.

Formula Used :-

$\sf\boxed{\bold{\large{v =\: u\: +\: at}}}$

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

Solution :-

Given :

• Initial velocity (u) = 4 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 10 seconds

According to the question by using the formula we get,

$\implies$ $\sf v =\: 4 +\: 2 \times 10$

$\implies$ $\sf v =\: 4 +\: 20$

$\implies$ $\sf\bold{\pink{v =\: 24\: m/s}}$

$\therefore$ The velocity of the car after 10 second is 24 m/s .

Extra Important Formula :-

$\mapsto$ First Equation Of Motion :

• $\leadsto$ $\sf v =\: u + at$

$\mapsto$ Second Equation Of Motion :

• $\leadsto$ $\sf s =\: ut + \dfrac{1}{2}a{t}^{2}$

$\mapsto$ Third Equation Of Motion :

• $\leadsto$ $\sf {v}^{2} =\: {u}^{2} + 2as$

where,

• s = Distance travelled or Displacement
• u = Initial velocity
• v = Final velocity
• a = Acceleration
• t = Time