Question

A car start with the initial velocity 36km/hr and acceleration 2m/s^2. find the distance covered by car in 10s​

Answer 1

Answer:

given

u=36km/h=36*5/18=10m/s

a=2m/s^2

t=10s

v=??

now using the first eq of motion

v=u+at

v=10+2*10

v=30m/s

now on using second eq of motion

s=ut+1/2at^2

s=10*10+1/2*2*10*10

s=100+100

s=200m ans

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Answer 2

Here, we will use the formula :-

[ v = u + at ]

where,

v, is the distance.

u, is the velocity.

a, is the acceleration,

t, is the time.

=> v = u + at

=> v = 36 + 2×10

=> v = 36 + 20

=> v = 56