a car start with the speed 60 km per hour from Prayag at 3 p.m. after one hours a second cars start with the speed at 80 km hr on the same track to cross the first car after how many kilometre the second car will be made the first car
Answers
Answer:
Given, P, Q, R and S are the mid-points of sides AB, AD, CD, and BC respectively.
Now, join AC, BD, PS, QR, PQ and RS
Since, P is the mid point of AB
So, AP = PB ........1
Since, Q is the mid point of BC
So, QC = QB ........2
Since, R is the mid point of CD
So, CR = RD ........3
Since, S is the mid point of AD
So, AS = SD ........4
Now, divide equation 1 by equation 4, we get
AP/AS = PB/SD
=> AP/PB = AS/SD
=> PS || BD .......5 {converse of Thales Theorem}
Similarly, QR || BD .......6
Again, From equation 5 and 6, we get
PS || QR .......7
Now, divide equation 1 by equation 2, we get
AP/QC = PB/QB
=> AP/PB = QC/QB
=> PQ || AC .......8 {converse of Thales Theorem}
Similarly, SR || AC ....9
From 8 and 9, PQ || SR .....10
From 7 and 10, PS | QR and PQ || SR
Hence, PQRS is a parallelogram
Read more on Brainly.in - https://brainly.in/question/10646284#readmoreGiven, P, Q, R and S are the mid-points of sides AB, AD, CD, and BC respectively.
Now, join AC, BD, PS, QR, PQ and RS
Since, P is the mid point of AB
So, AP = PB ........1
Since, Q is the mid point of BC
So, QC = QB ........2
Since, R is the mid point of CD
So, CR = RD ........3
Since, S is the mid point of AD
So, AS = SD ........4
Now, divide equation 1 by equation 4, we get
AP/AS = PB/SD
=> AP/PB = AS/SD
=> PS || BD .......5 {converse of Thales Theorem}
Similarly, QR || BD .......6
Again, From equation 5 and 6, we get
PS || QR .......7
Now, divide equation 1 by equation 2, we get
AP/QC = PB/QB
=> AP/PB = QC/QB
=> PQ || AC .......8 {converse of Thales Theorem}
Similarly, SR || AC ....9
From 8 and 9, PQ || SR .....10
From 7 and 10, PS | QR and PQ || SR
Hence, PQRS is a parallelogram
Read more on Brainly.in - https://brainly.in/question/10646284#readmore
Step-by-step explanation:
Answer:
It will be 2 hours