Question

A car starta from rest and acquires a velocity of 54km/h in 2 sec. Find
i) the acceleration
ii) distance travelled by the car (assume motion of car is uniform).

PLEASE ANSWER WITH EXPLANATION...​

Answer 1

given initial velocity of car is 54 km/ hr , time taken = 2s

converting 54km,hr into seconds ,

=. 54×5/18=15m s

now, acceleration = u-v/t

= 15-0/2= 7.5m / s ans

Now distance = (u+v)t/2

=(15+0)×2/2

= 15 ans