A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?
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Thank you for asking this question. Here is your answer.
FIrst of all I will provide you with the missing options of this question. Following are the options:
A. 20 km/hr
B. 40 km/hr
C. 60 km/hr
D. 80 km/hr
E. Cannot be determined
Answer:
The correct answer is B. 40 Km/hr
(x+40/s) + 5/4 = 40/s + 5x/4s (equation 1)
(x+40/s) + 1 = 80/s + 5(x-40)/4s (equation 2)
s = 40
If there is any confusion please leave a comment below.
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