Question

A car starting from 2m/s acquires a velocity of 8m/s in 4s .Calculate the acceleration.​

Answer 1

Answer:

u = 2m/s

v = 8 m/s

t = 4s

a = (v-u) /t

= (8-2) /4 m/s^2

=6/4m/s^2

= 1.5 m/s^2

Answer 2

Given:

• Initial Velocity = 2 m/s
• Final velocity = 8 m/s
• Time = 4s

To Find:

• Acceleration = ?

Solution:

• u = 2 m/s
• v = 8 m/s
• t = 4s

As we know

$\: \: {\large{\boxed{\sf{a = \frac{v - u}{t}}}}}$

Now substitute the values

$: \implies \sf\: a = \frac{8 - 2}{4} \\ \\ \\ : \implies \sf \: a = \cancel \frac{6}{4} \\ \\ \\ : \implies \sf \: a = \frac{3}{2} \\ \\ \\ : \implies \sf \: a = 1.5 \frac{m}{ {s}^{2} }$

$\therefore$Hence,acceleration of a car is 1.5 m/s^2.