Question

A car, starting from position of rest, moves with constant acceleration of x. Then it moves with constant deceleration y and becomes stationary. if the total time elapsed during this is t, what was be the maximum velocity of the car?
(1) xy/x-y (2) xy/x+y (3)x*x*y*y/x*x+y*y (4) x*x*y*y/x*x-y*y

Answer 1

Acceleration = ΔV / ΔT

Change in V in our case is the maximum velocity attained and change in T is the time achieved during acceleration.

1.) Acceleration :

T₁ = V (max) / x

2.) Deceleration

T₂ = V (max) / y

The total time is :

T = T₁ + T₂

V(max) / x + V(max) / y = T

V(max) = T / (1/x +1/y)

= T ÷ {(y + x) / xy}

T × xy /(y+ x)

The answer is :

xy /(y + x) given that t is a constant.

Answer 2

Answer:

Explanation:

Acceleration = ΔV / ΔT

Change in V in our case is the maximum velocity attained and change in T is the time achieved during acceleration.

1.) Acceleration :

T₁ = V (max) / x

2.) Deceleration

T₂ = V (max) / y

The total time is :

T = T₁ + T₂

V(max) / x + V(max) / y = T

V(max) = T / (1/x +1/y)

= T ÷ {(y + x) / xy}

T × xy /(y+ x)

The answer is :

xy /(y + x) given that t is a constant.