Question

A car starting from rest accelarates and the rate "a" through a distance "s" then continous at constant speed for time t and then comes to rest with returnation a by 2 if the total distance travel is 15 s then calculate the value of s in terms of a and t .

Answer 1

Answer:

Initial speed =0

Thus using the third equation of motion we can find the final velocity after moving a distance s.

After that the car moved at a constant speed for t time we can calculate the distance travelled:

Now after that it is decelerated by f/2 so we can find the distance covered as:

Now total distance travelled is 5s

Thus