A car starting from rest accelerates uniformly at 5 m /s^2 for 10 sec. Then it maintain uniform motion for next 5 sec . then the motion retards uniformly and comes to rest in 8 sec find the distance travelled by car?
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Answer:
Total distance covered is 700 metres.
Explanation:
WHEN THE CAR IS ACCELERATING:-
Intial Velocity = 0 m/s
Acceleration = 5 m/s²
Time taken = 10 s
By Equation :- s = ut + 1/2at²
we have, s = 250 m
Final velocity = u + at = 50 m/s
DURING UNIFORM MOTION:-
Distance = speed * Time = 50 m/s * 5 s = 250 m
DURING RETARDATION:-
Acceleration = (v - u) / t = -6.25 m/s²
∴ Distance = ut + 1/2at² = 200 m
TOTAL DISTANCE=
250 m + 250 m + 200 m =700 m.
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