Question

a car starting from rest accelerates uniformly to acquire a speed 20km h-1 in 30min. the distance travelled by car in this time interval will be:

Answer 1

u = 0km/h
v= 20km/h
t= 30/60 hr = 1/2hr
therefore, using first equation of motion
v=u+at
20=0+a(1/2)
20=a/2 => a =40km/h²
using second equation of motion
s=ut+1/2at²
s=0(1/2)+1/2(40)(1/2)²
s= 0+5 =5km
hope this helps

Answer 2

The distance traversed is 53.11 m.

Step-by-step process

Given:

Initial speed; u= 0 m$s^{-1}$

Final velocity; v= 20 km$h^{-1}$= 0.55 m$s^{-1}$

Time; t =30 min= 1800 seconds

To find =distance travelled

Solution:

Using the equations of motion;

v= u +at

0.55= 0+ 1800a

a= 3.05×$10^{-4}$ m$s^{-2}$

Using the equation;

$v^{2} -u^{2}= 2as$

We can find the distance,

$1800^{2} -0^{2} =$ 2×3.05 ×$10^{-4}$×s

324×$10^{4}$ =2×3.05 ×$10^{-4}$×s

324= 6.1×s

s= 53.11 m

Result:

The distance traversed is 53.11 m.

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