Question

A car starting from rest accelerates uniformly to acquire a speed 72 km/h in 10 sec. The distance travelled by the car in this time interval will be

600 m

5 km

100 m

240 km​

Answer 1

Answer:

s=100 m

Explanation:

Given  

u=0

v=72 km/h = 20 m/s

t= 10 seconds

a=  v-u/t

  = 20-0/10​  

a = 2  

s=ut+  1/2(at^2)

putting values

= 0(10) + 1/2 (2*10^2)

0 + 1/2(2*100)

s = 1/2(200)

s = 100 m