A car starting from rest acquired a velocity 180m/s in 0.05h find the accerlartion
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given: u=0m/s
v=180m/s
t=0.05h= 60×5/100=3s
v=u+at
v=at
a=v/t=180÷3=60m/s^2
therefore the acceleration is 60m/s^2
hope it helped
mark it as brainliest too please
v=180m/s
t=0.05h= 60×5/100=3s
v=u+at
v=at
a=v/t=180÷3=60m/s^2
therefore the acceleration is 60m/s^2
hope it helped
mark it as brainliest too please
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