Question

A car starting from rest acquired a velocity of 18m/s in 6s.Calculate the acceleration .If 70N force applied then find the mass of car


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Answer 1

Given,

Initial velocity u=180m/s

Time t=0.05 h=0.05×3600 s

Assuming constant acceleration

v=u+at

⇒180=0+a(0.05×3600)⇒a=1m/s

2

Answer 2

Answer:

$\pink{ \boxed { \bigstar \sf \: \sf acceleration \: \: a = 3 \: m {s}^{ - 2} }} \\ \\ \orange {\boxed{ \sf\: \bigstar \sf \:mass \: m = 23.33 \: kg}} \:$

Explanation:

Given,

$\odot \sf \: initial \: velocity \: \: u = 0 \\ \odot \sf \: final \: velocity \: \: v = 18 \: m {s}^{ - 1} \\ \odot \sf \: time \: \: t = 6 \: s \\ \odot \sf \: force \: \:F = 70 \: N$

To find :

$\pink{ \bigstar \sf \: acceteration \: \: = a} \\ \orange{ \bigstar \sf \:mass \: of \: the \: car \: = \: m }$

Solution :

we know that,

$\pink{ \large{ \sf \: acceleration \: \: a = \frac{v - u}{t} }} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \pink{ \sf \: = \frac{18 - 0}{6} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \pink {\sf \: = 3 \: m {s}^{ - 2} } \\ \\ \pink{ \boxed {\therefore \sf acceleration \: \: a = 3 \: m {s}^{ - 2} }}$

Again, we know that

$\: \: \: \: \: \: \: \: \: \: \: \orange{\sf \: F = ma} \\ \orange{ \implies \sf \: m = \frac{F}{a} = \frac{70}{3} } \\ \: \: \: \: \: \: \orange{\sf \: m = 23.33 \: kg} \\ \\ \orange {\boxed{ \sf\therefore \: mass \: m = 23.33 \: kg}}$