A car starting from rest acquires a velocity of 54 km/h in 5 seconds. calculate its acceleration and displacement .
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Answered by
20
Answer :
➥ Acceleration of the car = 7.5 m/s²
➥ Displacement of the car = 15 m
Given :
➤ Intial velocity of the car (u) = 0 m/s
➤ Final velocity of the car (v) = 54 km/h
➤ Time taken (t) = 2 sec
To Find :
➤ Acceleration of the car (a) = ?
➤ Displacement of the car = ?
Solution :
◈ Final velocity (v) = 54 km = 54 × ⁵/₁₈ = 15 m/s
Acceleration is given by
Hence, the acceleration of the car is 7.5 m/s².
Now ,
We calculate displacement of the car
From second equation of motion
Hence, the displacement of the car is 15 m.
⠀
Some releted equations :
⪼ s = ut + ½ at²
⪼ v = u + at
⪼ v² = u² + 2as
Answered by
5
☛︎ Initial velocity of the car, u = 0 (at the rest)
☛︎ Final velocity of the car, v = 54 km/h = 15m/s
☛︎ Tme taken, t = 5 seconds
- Acceleration of the car, a = ?
- Displacement of the car, s = ?
NOW,
Therefore, Acceleration of the car is 3m/s² and
Displacement of the car is 37.5 m
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