Question

A car starting from rest acquires a velocity of 54Kmph in 5s. The acceleration of the car is ………..m/s2​

Answer 1

Answer:

Answer

As the car is starting from rest,

Initial velocity = u=0m/s

Final velocity = v=54km/hr

To convert km/hr to m/s, we multiply it by 5/18

Final velocity = v=54km/hr=54×5/18

=15m/s

Time = t=2 sec

a = acceleration

Equation of motion:

v=u+at

15=0+2a

a=15/2=7.5m/s

2

s = distance travelled

Equation of motion:

s=ut+1/2at

2

=0+1/2×7.5×2

2

=15 metres

Answer 2

Explanation:

v= 54 km/h = 54*5/18 = 15 m/s

u=0

t=5 sec

Applying first equation of motion

$v = u + at$

$a = \frac{v - u}{t}$

$a = \frac{15 - 0}{5}$

$a = 3$

a=3m/s^2

Hope it helps

Dhairya Mittal signing off