A car starting from rest acquires speed of 20m/s in covering a distance of 100m.Calcualate the acceleration of the car
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Given:-
- Initial velocity, u = 0 m/s( As the cars starts from rest)
- Final velocity, v = 20 m/s
- Distance covered by the car, s = 100 m.
To Find:-
- What is the acceleration of the car?
Solution :-
- We know third law of motion is given by v² = u² + 2as.
Putting the given values :-
⇢v² = u² + 2as
⇢ (20)² = (0)² + 2×a× 100
⇢ 400 = 0 + 200a
⇢200a = 400
⇢ a = 400/200
⇢ a = 2 m/s²
- Hence, the acceleration of the car is 2 m/s².
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