A car starting from rest acquires the velocity of 15m/s in 5second calculate its acceleration and distance moved by it
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Answered by
7
acceleration =dv/dt so=15÷5=3
distance=1/2at^2=37.5
distance=1/2at^2=37.5
ashutosh6343:
theek he
yaa
and thanks......go it aur rest PE bhi tha......I didn't seee
PE kya
# rest mai thai
PE kya potential energy
nahi
phit kya he
phir kya he
face book pe he kya
Answered by
0
Answer:
V=15m/sec
U=0
t=5sec
a=v-u/t
according to the given value
15-0/5
3m/sec
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