Question

a car starting from rest and cover a distance of 200 m in 4 seconds The acceleration of the car is?​

Answer 1

Explanation:

Initial velocity(u)=0

Distance(s)=200m

Time taken (t)= 4 seconds

We know that

s=ut+1/2at^2

200m=0×4+1/2a(4)^2

200m=0+8a

8a=200

so a=200/8

a=25

Acceleration is 25m/sec^2