Question

A car starting from rest and moves with a constant acceleration of 2 m/s^-2 for 10 seconds calculate the velocity of the car after 10 seconds

Answer 1

Given -

• Initial velocity (u) = 0
• Acceleration (a) = 2 $\sf{m/s^2}$
• Time (t) = 10 seconds

To find -

• Velocity of the car after 10 seconds.

Solution -

• v = u + at

Substitute the given values.

↬ v = 0 + 2 × 10

↬ v = 20 m/s

$\overbrace{\underbrace{\sf{\green{Velocity = 20 m/s}}}}$

━━━━━━━━━━━━━━━━━━━━━━

Know more -

Velocity -

• It is distance travelled by a body in one second in a particular direction.

• It is a vector quantity.

• Its S.I. unit is m/s.

Acceleration -

• It is the rate of change of velocity of a body.

• It is vector quantity.

• Its S.I. unit is $\sf{m/s^2}$

Equations of motion -

• First equation of motion -

v = u + at

• Second equation of motion -

s = ut + $\sf{\dfrac{1}{2} at^2}$

• Third equation of motion -

$\sf{v^2 - u^2 = 2as}$

where,

v = Finial velocity

u = Initial velocity

a = acceleration

s = distance/displacement

t = time

Answer 2

Given :

• Initial velocity, u = 0 m/s (as it is starting from rest)
• Acceleration, a = 2 m/s²
• Time, t = 10 seconds

To find :

• Final velocity, v

According to the question,

By using Newtons first equation of motion,

→ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

→ Substituting the values,

→ v = 0 + 2 × 10

→ v = 0 + 20

→ v = 20

So,the final velocity is 20 m/s.

______________________

More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as