Question

A car starting from rest and moving along a straight path with uniform acceleration covers distances p and q in the first two successive intervals of time. Find the ratio of p to q.

Answer 1

Let the time intervals be 't' seconds each, and the distances covered after t seconds and 2t be x1 and x2 respectively. ( Dont take the 1 and 2 as powers, they are subscripts here)

Then, from the question, p=x1 and q=x2-x1.

Then from the 2nd equation of motion, since intial velocity is 0(ie. u=0), so

x1= (1/2)∗at2 = 1/2 a(t^2)

And, x2= (1/2)∗a(2t)2 = 2a(t^2)

Where a is the constant acceleration.

So, p=1/2 a(t^2)

And q=2a(t^2)-1/2a(t^2) = 3/2a(t^2)

So p/q=1/3

Answer 2

Answer:

answer = p/q = 1/3

Thank you