A car starting from rest and moving on a straight road whit 2ms-2 acceleration is observed for 10 seconds Find (1) the distance travelled by the car in this time (2) the velocity at the end of this time
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We have given
acceleration = 2m/s²
time = 10 sec
Since car start from rest so intial velocity will be zero so
u = 0
We have formula S = ut +½×at²
put u = 0, a= 2m/s² , t = 10
S = 0 + ½× 2×(10)²
S = 100m
And we have formula
v²-u² =2as
Here u = 0 , a =2m/s² , s= 100
v² -0² = 2×2×100
v² =400
v =20m/s
So Distance travelled =100m
Final velocity = 20m/s
acceleration = 2m/s²
time = 10 sec
Since car start from rest so intial velocity will be zero so
u = 0
We have formula S = ut +½×at²
put u = 0, a= 2m/s² , t = 10
S = 0 + ½× 2×(10)²
S = 100m
And we have formula
v²-u² =2as
Here u = 0 , a =2m/s² , s= 100
v² -0² = 2×2×100
v² =400
v =20m/s
So Distance travelled =100m
Final velocity = 20m/s
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