Question

a car starting from rest and moving on a straight road with 2 m/s² acceleration is observed for 10 sec.
(i) The distance travelled in this time.
(ii) The velocity at the end of this time.

Answer 1

s = ut + 1/2 at^2
s = 0 + 1/2×2×10×10
s = 200/2 = 100m
v = u + at
v = 0 + 2×10
v = 20m/s

Answer 2

since the distance = speed × time
= 2 × 10 = 20 m

the velocity acceleration = velocity/time
velocity = acceleration × time
20 m/sec

hope u got this