Question

a car starting from rest and moving on astrqight road with 2 m/ s2 acceleration is observed in 10 sec
1 the distance travelled in this time
2. the velocity at the end of this time

Answer 1

distance is 100 and final velocity is 20 m/s...
but not sure

Answer 2

2 the velocity at the end can be find by first equation of motion
$v = u + at ^{2}$
so
$u = 0 \: as \: it \: strat \: from \: rest \\ a = 2m \: per \: seconde \: square \\ t = 10s$
$0 + 2 \times 10 = 20m \: per \: seconde$
1
it can be solved by seconds equation of motion
$s = ut + at ^{2}$
$v = 20 \: meter \: per \: seconde$
$so \: 0 \times 10 + \frac{1}{2} \times 2 \times 10 ^{2}$