A car starting from rest and moving with uniform accelaration on a straight road travels for sometime such that the paths described by it in the last second and in the penultimate second of its motion are in the ratio 4:3, respectively. Calculate the total time traveled by the body.
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Answered by
7
Answer:
the total time traveled by the body. is = 4.5 seconds
Step-by-step explanation:
Let t be the total time taken of the journey....
as body is initially at rest , u=0.,
distance travelled by the body in last second .,
St= u+a/2(2t-1).
St=0+ a/2(2t-1).
distance travelled by the body in penultimate second .,
St-1= a/2(2(t-1)-1).
St/St-1=2t-1/2t-3.
4/3=2t-1/2t-3.
8t-12=6t-3.
2t=-3+12.
2t=9.
t=4.5 seconds.
Answered by
0
Answer: Let T be the total time.
we know that, U=0
distance travelled by the body in the last second is
St= u+a/2(2t-1).
St=0+ a/2(2t-1).
distance travelled by the body in the penultimate second is
St-1= a/2(2(t-1)-1).
St/St-1=2t-1/2t-3.
4/3=2t-1/2t-3.
8t-12=6t-3.
2t=-3+12.
2t=9.
t=4.5 seconds.
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