a car starting from rest at and simplicity of 60 km per hour in 10 minutes calculate the acceleration and distance travelled by a car assuming in that association for uniform
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I Think the answer is 1.66m/s² the above picture will help you
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sanjeevkumar20:
wrong answer but no problem the answer is 6 metre per second square
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hey friends
here,
u ( initial velocity)= 0
v (final velocity)= 60 = 60×5/18 =16.6m/s
time=10 minutes=10×60=600seconds
so,
acceleration=v-u/t
= 16.6-0/600
= 0.027m/s^2
distance=speed×time
16.6×600
=9960m/s
I HOPE MY ANSWER WILL HELP YOU
here,
u ( initial velocity)= 0
v (final velocity)= 60 = 60×5/18 =16.6m/s
time=10 minutes=10×60=600seconds
so,
acceleration=v-u/t
= 16.6-0/600
= 0.027m/s^2
distance=speed×time
16.6×600
=9960m/s
I HOPE MY ANSWER WILL HELP YOU
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