A car starting from rest attains a velocity of 125/9 m/s and travels 250km. What is the acceleration of the body?
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s=9km=9000m
This motion is in three phases.
[Case: 1]
with acceleration, a=0.2ms−2 and intial velocity , u=0
Thus using equation v=u+at
10=0+0.2×t
So, t=50 s
[Case: 2]
uniform motion with velocity ,v=10
and distance, s=9000
Thus time , t=vs=109000=900 s
[Case: 3]
With acceleration, a=−0.1ms−2
u=10ms−1
and v=0
Thus using equation v=u+at
0=10−0.1×t
So, t=0.110=100 s
Therefore
Total time = 50s+900s+100s=1050s
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