Question

A car, starting from rest attains a velocity of 60 km/h in 10 s. find the acceleration of the car.​

Answer 1

Distance=Speed×Time.

Distance=60×10km.

Therefore,Distance=600km.

According to the question,we have to find acceleration.

So,a=v-u/t.

60km/h=$\frac{60×5}{8}$ =16.67m/s.

Let acceleration be x.

x=600-16.67/5.

x=583.33/5.

x=166.66m/s.

Therefore,Acceleration is 166.66m/s which is x value.

Answer 2

Acceleration - Motion

Acceleration is defined as the rate of change in velocity with respect to time. It is measured as metre per second square. In Mathematically,

$\implies \boxed{\bar{a} = \dfrac{\Delta v}{\Delta t}}$

Where, ā denotes acceleration, ∆v denotes change in velocity (v - v₀) and ∆t denotes total time taken or time interval.

As per the question, A car starts from rest and attains a velocity of 60 km/h in 10 seconds. It means the initial velocity of 0km/h and the final velocity is 60km/h.

We know that, to convert the unit from km per hour to m per second we have to divide the velocity value by 3.6. [You can also multiply the velocity value by 5/18 to convert the velocity from km per hour to m per second]

Initial velocity, u = 0/3.6 = 0m/s

Final velocity, v = 60/3.6 = 16.66m/s

Now we know that, acceleration is the rate of change in velocity with respect to time. Therefore,

$\implies \bar{a} = \dfrac{\Delta v}{\Delta t} \\ \\ \implies \bar{a} = \dfrac{u - v}{t}$

Now substituting the known values in the above equation/formula, we get:

$\implies \bar{a} = \dfrac{16.66 - 0}{10} \\ \\ \implies \bar{a} = \dfrac{-16.66}{10} \\ \\ \implies \boxed{\bar{a} = -1.666}$

Hence, the acceleration of the car is -1.666m/s².