a car starting from rest attains a velocity of 72 km per hour in 20 seconds find the force exerted on the car if its mass is 100 kg also find initial Momentum and final momentum
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F=100 N
initial momentum=0
final momentum=2000 kgm/s
initial momentum=0
final momentum=2000 kgm/s
piyush8435:
i want full solution how it comes
u=0, v=72 m/s=20 m/s, m=100 kg.a=v-u/t a=20-0/20=1 m/s^2 F=ma F=100N. initial momentum=mu=o. final momentum=100×20=2000kgm/s
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as car is starting from rest
u=0
v=72 km/h
we have to convert it into m/s
=72x1000/3600
=20m/s = v
a=v-u/t
f=ma
=m(v-u/t)
=100(20/20)
f=100N
initial momentum = mu = 100x0 = 0 kgm/s
final momentum = MV = 100*20 = 2000 kgm/s
u=0
v=72 km/h
we have to convert it into m/s
=72x1000/3600
=20m/s = v
a=v-u/t
f=ma
=m(v-u/t)
=100(20/20)
f=100N
initial momentum = mu = 100x0 = 0 kgm/s
final momentum = MV = 100*20 = 2000 kgm/s
thanks
i have again 1 que may i ask
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