a car starting from rest attains the speed of 90 kilometre per hour in 10 seconds and in next 20 second it again comes to restwhat will be the acceleration of car in both cases
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FIRST CASE-
The car is starting from rest,so u=0m/s
V=90km/h=25m/s
T=10seconds
a=v-u/t =(25-0)/10 =25/10 =2.5m/s
SECOND CASE
u=90km/h =25m/s
v=0m/s
t=20m/s
a=v-u/t =0-25/20 = -25/20 = -2.5m/s
(THE NEGATIVE SIGN SHOWS SEACCELERATION ...MEANS THAT THE SPEED IS DECREASINH)
The car is starting from rest,so u=0m/s
V=90km/h=25m/s
T=10seconds
a=v-u/t =(25-0)/10 =25/10 =2.5m/s
SECOND CASE
u=90km/h =25m/s
v=0m/s
t=20m/s
a=v-u/t =0-25/20 = -25/20 = -2.5m/s
(THE NEGATIVE SIGN SHOWS SEACCELERATION ...MEANS THAT THE SPEED IS DECREASINH)
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