a car starting from rest attaints a velocity of 60km/h in 10 s. find the acceleration of the car
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1
a=v-u
t so 0 - 60
10
the answer is 6
see v means intial velocity
u means final velocity
t means time 0-60 upon 10 =6
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t so 0 - 60
10
the answer is 6
see v means intial velocity
u means final velocity
t means time 0-60 upon 10 =6
if u like so pls mark as brainlest
aashnasiddiqui:
a means acceleration
V means final velocity
u means initial velocity
t means time
so 60÷10 =6
but the corretct answer in book 5/3m/s²
see again
so see we can cut this with 2 so first 00cut then 2 ÷6 is 3 and 2 ÷10 is 5so 5/3m/s
na under stood
Answered by
3
v1=0,t1=O
v2= 60×1000/3600
=600/36
=100/6
=1.66m/s
t2=10 s
acceleration= v2-v1/t2-t1
=1.66-0/10-0
=0.166mls*2
v2= 60×1000/3600
=600/36
=100/6
=1.66m/s
t2=10 s
acceleration= v2-v1/t2-t1
=1.66-0/10-0
=0.166mls*2
but lenghty
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