Physics, asked by Neetstruggler, 10 months ago

A car starting from rest first accelerates with 6m/s^2, then suddenly decelerates with 3m/s^2 till it stops. if total time of journey is 10 sec, then the maximum speed acquired by the car is (1) 10m/s (2)20m/s (3)30m/s (4)35m/s with a correct explanation please!!
*Motion in straight line*​

Answers

Answered by Akshavya
3

Answer:

V=20 m/s is the velocity

Explanation:

U=0

Let Total time be t=10 divides into two parts t1 and t2 respectively

Now case 1

From u=0 to v=V ie acceleration +ive

V=6t1

t1=V/6

Case 2:

From U=V to v=0

-V=-3t2

t2=V/3

Total time t=10s

ie 10=t1+t2

10=V/6+V/3

10=3V/6

10=V/2

V=20 m/s

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