Question

a car starting from rest has a soeed of 30km/h at any one instant two seconds later it's speed is 36km/h and after two second it is 42km/h. if it continues accelerate luke this what will be it's speed after 8s and 8s at that instant​

Answer 1

Explanation:

For fiest instant,

v = u + at

30 = 0 + a*t............(1)

After 2 seconds that is after (t+2)

36 = 30 + a(t+2)

or

6 = at + 2a..........(2)

solving both eqns we get,

2a = -24

a = -12 m/s^2.

which could not be possible as it has travelled further more after these 2 seconds but the accln is deccelation.

Hence not possible.