Question

a car starting from rest has an acceleration 0.3 m/s^2, calculate the velocity and distance traveled by this car after 2 minutes

Answer 1

Explanation:

1) velocity , v = u + at

= 0 + ( 0.3 × 2×60 ) m/s

= 0.6 × 60 m/s

= 36 m/s

2) displacement, s = vt

= ( 36 × 2 ) m

= 72 m

Answer 2

Explanation:

Car has started from rest so, initial velocity becomes 0

Acceleration = Final velocity - Initial velocity/ Time

OR

A = V - U / T

Given,

a = 0.3 m/s^2

u = 0 m/s

t = 2 minutes

t = 120 seconds

v = ?

a = v - u / t

0.3 = v - 0 / 120

v = 0.3 × 120

v = 36 m/s Answer

Hope it helps you.....