A car starting from rest is accelerated at constant rate untill it attains a constant speed v. It is then retarded at a constant rate untill it comes to rest. Considering that the car moves with a constant speed for half of the time of total journey, the average speed of the car for the journey is
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V=distance
_______
time
Let the total time be t.
Average speed for 1st interval of t /4 is v/2
For 1st interval, s1 = 2/v × 2/t
Average speed for 3rd interval of t/4 is v/2
For 3rd interval, s3 = v/2 × t/2
For 2nd interval, s2 =v× t/2
Total distance d=s1+s2+s3
Total time is t
V av g=d/t = 3v/4
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