Physics, asked by rajeevjnp, 5 hours ago

A car starting from rest is accelerated uniformly at the rate of 2 m/s^2. Determine the velocity of the car when it covers a distance of 50 m.
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Answers

Answered by Anonymous
4

Provided that:

  • Initial velocity = 0 m/s
  • Acceleration = 2 m/s sq.
  • Distance = 50 m

To calculate:

  • The final velocity

Solution:

  • The final velocity = 14.14 m/s

Using concept:

  • Third equation of motion

Using formula:

  • v² - u² = 2as

Required solution:

→ v² - u² = 2as

→ v² - (0)² = 2(2)(50)

→ v² - (0)² = 2(100)

→ v² - 0 = 200

→ v² = 200

→ v = √200

→ v = 14.14 m/s

→ Final velocity = 14.14 m/s \:

Answered by anshvanshtyagi4
0

Answer:

14.14 m/s^2

Explanation:

We have to solve this from 3rd Equation of Motion i.e. 2as = v^{2}-u^{2}

We know that car started from rest so its initial velocity will be 0 m/s.

So,

  • Initial Velocity = 0 m/s
  • Acceleration = 2 m/s^2
  • Distance = 50 m  

  So,  2as = v^{2}-u^{2}

          2×2×50 = v^{2} - 0^{2}

          200 = v^{2}

          v=\sqrt{200}

         v = 14.14 m/s

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anshvanshtyagi4

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