Question

A car
starting from rest maintained and acceleration of 0.2 metre per second square up two minutes now find the distance cover in the given time​

Answer 1

Answer:

As we know that,

S = ut + 1/2at^2 . . . . . . . . . 1

Here, a =2 m/s^2 , u = 0 (as the car starts from rest)

And t = 4 sec.

From equation 1

S = 0 + 1/2×2×4×4

S = 16 m

Now we also know that,

V^2 = u^2 + 2aS

V^2 = 2aS ( as u =0 )

V^2 = 2×2×16

V^2 = 64

Explanation:

Answer 2

Answer:

a=0.2m/s²

t=120s/2min

u=0

s=ut+ (at²)/2

s=0(140)+(0.2)(120)²/2

s=0.2*14400/2

s=0.2*7200

s=20*72

s=1440m