Question

A car starting from rest moves along a straight line with constant acceleration of
5 m/s2 for 10 seconds, then it moves with constant velocity. Calculate the distance
travelled by car in 15 seconds from the start?​

Answer 1

Answer:

s

1

=ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

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