Question

A car starting from rest moves with a uniform acceleration of 0.2 m/s∧2 for 2 min. Find the speed acquired and the distance travelled

Answer 1

Answer:

a=0.2m/s^2

t=2 min=120s

u=0m/s

v=?

by First equation of motion

v=u+at

=0+(0.2)(120)

=2*12

=24m/s

Now,

by second equation of motion

s=ut+1/2at^2

=(0)(120)+(1/2)(0.2)(120) (120)

=(1/2)(2)(12)(120)

=1440m

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Answer 2

Explanation:

1440 m is the answer

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