A car starting from rest moves with uniform acceleration of 2.5 ms-2 for 5 mins. Find the speed and distance travelled
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acceleration of 2.5 ms-2 for 5 mins. Find the speed and distance travelled
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Initial velocity, u=0m/s
Final velocity, yv=?
Acceleration, a=0.2m/s
2
Time, t=5min=5×60=300sec
Using first equation of motion to obtain the final speed:
v=u+at
v=0+0.2×300=60m/s
And the distance travelled is
s=ut+
2
1
αt
2
s=0×300+
2
1
×0.2×300×300
s=0+9000=9000m=9km
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