A car starting from rest, pickup velocity of 45m/sec over a time of 70 sec. Find the acceleration of the car.
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Hey there,
Accordding to the Newton's 1st law of motion-
v=u+at
a=v-u/t
Since v=45 m/s
u=0 m/s
t=70 s
a=45/70=0.6428 m/s²
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Accordding to the Newton's 1st law of motion-
v=u+at
a=v-u/t
Since v=45 m/s
u=0 m/s
t=70 s
a=45/70=0.6428 m/s²
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
AnjaliAnju1:
thanks
Can you just give me a small explanation
welcome
Hi there,
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
small exp about what???
v=u+at 45*5/18=0+a70 a=
okkk
45=0+a*70 a=45/70 a=9/14m/s^2
It is starting from rest so the initial velocity (u) should be zero and the final will be 45 m/sec
plz mark as brainliest
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