Question

a car starting from rest requires a velocity 72km/hr in 8 seconds...calculate its acceleration nd distance moves by it ​

Answer 1

Answer:

Explanation: First convert 72 km/hr in m/s for solving the question easily.

I.e. 72×5/18=20m/s

Now we know initial velocity (u)=0. (Because particle was initially at rest)

Acceleration= change in velocity /time=v-u/t

=20-0/8

=2.5 m/s^2

Answer 2

Answer:acceleration is 2.5 and distance is 80

Explanation:

Apply v= u+at u=0 ; v=20m/s ; t= 8

Now find a ie acceleration

After that apply s= u+1/2at × t and s ie displacement which is here equal to distance