Question

A car starting from rest travelled with a speed of 27m/s in 3s.Find the acceleration of the body​

Answer 1

Answer:

9m/square

Explanation:

a= v-u/t

27-0/3

9m/square

Answer 2

Information given to us:

• Speed of car is 27m/s
• Time taken by car is 3s

Need to be calculated:

• Acceleration of the body

Applicable formula:

• s = ut + (1/2) at²

Performing calculations:

Here we have been provided with the values of speed and time taken, whereas we have to calculate the acceleration.

In this given above formula,

• a denotes acceleration
• s denotes displacement
• t denotes time

Remember that speed of car is only displacement which is 27 m/s.

Now substituting the required values in the given formula of displacement.

➳ 27 = 0 × 3 + (1/2)(a)(3)²

➳ 27 = 0 × 3 + (1/2) × a × 3 × 3

➳ 27 = 0 × 3 + (1/2) × a × 9

➳ 27 = (1/2) × a × 9

Transposing sides from R.H.S to L.H.S.,

➳ 27/9 = (1/2) × a

Now,

➳ 9/3 = (1/2) × a

➳ 3 = (1/2) × a

➳ 3 = (1/2)a

➳ 3×2= a

At last we gets,

➳ a = 6

Conclusion:

• Acceleration of the body is 6m/s $\:$