Question

A car starting from rest travels with uniform acceleration.if it covers 200m in 10second calculate the acceleration of the car

Answer 1

Given :

Distance covered by car = 200m

Time taken by car = 10s

Initial velocity = zero

To Find :

Acceleration of the car$.$

Solution :

■ In this case, car is moving with constant acceleration.

• We can apply equation of kinematics when body has constant acceleration.

Second equation of kinematics is given by

• d = ut + 1/2 at²

➛ d denotes distance

➛ u denotes initial velocity

➛ a denotes acceleration

➛ t denotes time

Initial velocity (u) = zero

By substituting the given values;

➠ d = ut + 1/2 at²

➠ 200 = (0)(10) + 1/2 a (10)²

➠ 200 × 2 = 100a

➠ 100a = 400

➠ a = 400/100

➠ a = 4 m/s²

Answer 2

Answer:

question:-

A car starting from rest travels with uniform acceleration.if it covers 200m in 10second calculate the acceleration of the car

Given:-

• inital Velocity = 0
• distance covered = 200 metre
• time taken = 10 sec

To find :-

acceleration of the car.

Solution:-

☆According to second equation of kinematics-

$\purple{\to \sf \: s = ut + \frac{1}{2} a {t}^{2} }$

where

» s denotes Distance.

» u denotes inital Velocity.

» a denotes accleration.

» t denotes time.

➝substitute the values in the above equation of kinematics-

$\sf {\to \: 200 = 0 + \frac{1}{2} \times a \times ( {10})^{2} } \\ \\ \sf{\to 200 = a \times 50} \\ \\ \sf{\to \: a = \frac{200}{50}}\\ \\ \sf \pink{\to \: a = 4m/sec}$

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equations of kinematics-

1. V= u+at

2. s= ut+1/2at²

3. v²= u²+2as

where

» s denotes Distance.

» u denotes inital Velocity.

» a denotes accleration.

» t denotes time.

»v denotes final velocity.

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