Physics, asked by khobendrakemprai, 8 months ago

A car starting from rust attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform,find the distance travelled by the car for attaining this velocity.

Answers

Answered by shyamananda
4

Answer:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Explanation:

Hope it helps

Answered by BrainlyIAS
4

Answer

  • Distance travelled by the car for attaining this velocity is 3 km

Given

  • A car starting from rest attains a velocity of 72 km/h in 5 minutes.

To Find

  • Assuming that the acceleration is uniform,find the distance travelled by the car for attaining this velocity

Solution

Initial velocity , u = 0 m/s

Final velocity , v = 72 km/h = 72 * (5/18) = 20 m/s

Time , t = 5 min = 300 s

We know that , " Acceleration is defined as the rate of change of velocity "

⇒ Acceleration , a = ( v - u ) / t

⇒ Acceleration , a = ( 20 - 0 ) / 300

⇒ Acceleration , a = 1/15 m/s²

Distance , s = ? m

Now , use 3rd equation of motion .

v² - u² = 2as

⇒ 20² - 0² = 2 ( 1/15 ) s

⇒ 200 = 1/15 s

s = 3000 m

s = 3 km

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