A car starting from rust attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform,find the distance travelled by the car for attaining this velocity.
Answers
Answered by
4
Answer:
v=u+at
a=(v-u)/t -----------(1)
v=72 km/h
=20m/s
u=0
t=5*60 sec =300sec
by putting values of v,u,t in (1)
a=1/15 m/s2
s=ut +(1/2)at2
=0+(1/2)(1/15)(300)(300)
=3km
Explanation:
Hope it helps
Answered by
4
Answer
- Distance travelled by the car for attaining this velocity is 3 km
Given
- A car starting from rest attains a velocity of 72 km/h in 5 minutes.
To Find
- Assuming that the acceleration is uniform,find the distance travelled by the car for attaining this velocity
Solution
Initial velocity , u = 0 m/s
Final velocity , v = 72 km/h = 72 * (5/18) = 20 m/s
Time , t = 5 min = 300 s
We know that , " Acceleration is defined as the rate of change of velocity "
⇒ Acceleration , a = ( v - u ) / t
⇒ Acceleration , a = ( 20 - 0 ) / 300
⇒ Acceleration , a = 1/15 m/s²
Distance , s = ? m
Now , use 3rd equation of motion .
⇒ v² - u² = 2as
⇒ 20² - 0² = 2 ( 1/15 ) s
⇒ 200 = 1/15 s
⇒ s = 3000 m
⇒ s = 3 km
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