A car starts at 36 km/h towards east. After 10 minutes, it turns towards north and travels af a rate of 18 km/hr for the next 10 minutes. What is it's average speed and velocity?
Answers
Answer:
27 km/h
Explanation:
first vel.(v)=36 km/h
first time(t)=10 min=1/6 h
first distance=v×t
=36×1/6= 6 km
second vel.(v')=18 km/h
second time(t')=1/6 h
second distance=v'×t'
=18×1/6=3 km
total dist.=6+3 km=9 km
total time=1/6+1/6=1/3 h
avg. vel.=total dist./total time
=9÷1/3=9×3
=27 km/h
Explanation:
speed= distance/ time
change km/ hr to m/sec
change time mins to sec
speed= 36x5/18= 10 m/sec
18x5/18= 5m/sec
distance traveled in North direction
10m/sec = d 1/10x60
d1= 6000m
distance traveled in East direction
5m/sec = d2/10x60
d2= 3000m
a.v speed = total distance/ total time
= 3000+6000/20x60
= 7.5 m/s
a.v velocity= total displacement/total time
= 3000+6000/20x60
= 7.5m/s