Question

A car starts at one vertex of a square track of side 125 m and reaches the starting point in 50 s. The speed of the car is

Answer 1

Answer:

d=125m=1000m

t=50s

s=d/t

=1000/50

s=20m/s

therefore speed of the car is 20m/s.

Answer 2

Answer:

12 m/s

Explanation:

As given in question,

side of square path on which car is moving = 125 m

Since, the car reach to its starting point so the total distance traveled by car=  4 x 125 m

  = 600 m

time taken by car to reach its starting point = 50 s

Since, we have to calculate sped of car,

$\textrm{speed}\ =\ \dfrac{\textrm{distance}}{\textrm{time}}$

           $=\ \dfrac{600}{50}\ m/s$

             $=\ 12\ m/s$

So, the speed of car will be 12 m /s.