Question

a car starts at point A with a velocity of 12 m/s. If it has a steady acceleration of 3 m/s2, what is the velocity 5 seconds later ehen it reaches point B?​

Answer 1

➣ Answer

• Final velocity of the car = 27m/s.

➣ Given

• Initial velocity of the car = 12m/s.
• Acceleration of the car = 3m/s².
• Time = 5 seconds.

➣ To Find

• Final velocity of the car.

➣ Step By Step Explanation

Given that ⤵

• Initial velocity of car = 12m/s.
• Acceleration of car = 3m/s².
• Time = 5 seconds.

We need to find final velocity of the car.

So let's do it !!

➵ By using first equation of motion

• v = u + at

➵ By substituting the values

$\longmapsto \tt \: v = 12 + 3 \times 5 \\ \\\longmapsto \tt v = 12 + 15 \\ \\\longmapsto{\tt{ \color{purple}v = 27m/s}}$

Therefore, final velocity of the car = 27 m/s

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➣ Equations of motion

There are mainly three equations of motion. They are as follows -

1. v = u + at
2. s = ut + ½at²
3. v² - u² = 2as

Where, u = initial velocity , v = final velocity, t = time, a = acceleration, and s = distance travelled.

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