a car starts at point A with a velocity of 12 m/s. If it has a steady acceleration of 3 m/s2, what is the velocity 5 seconds later ehen it reaches point B?
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➣ Answer
- Final velocity of the car = 27m/s.
➣ Given
- Initial velocity of the car = 12m/s.
- Acceleration of the car = 3m/s².
- Time = 5 seconds.
➣ To Find
- Final velocity of the car.
➣ Step By Step Explanation
Given that ⤵
- Initial velocity of car = 12m/s.
- Acceleration of car = 3m/s².
- Time = 5 seconds.
We need to find final velocity of the car.
So let's do it !!
➵ By using first equation of motion
- v = u + at
➵ By substituting the values
Therefore, final velocity of the car = 27 m/s
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➣ Equations of motion
There are mainly three equations of motion. They are as follows -
- v = u + at
- s = ut + ½at²
- v² - u² = 2as
Where, u = initial velocity , v = final velocity, t = time, a = acceleration, and s = distance travelled.
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