Question

A car starts at rest and acquires a velocity of 70 kph in 20 minutes. find?
a. Acceleration
b. the distance traveled i the first 20 mins
c. the distance traveled in the next 20 more mins.

Answer 1

Hope u like my process
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Velocity of car after 20 min (v) = 70 km/hr

Time (T) = 20 min = 20/60 = ⅓hr

Initial velocity (u) = 0km/hr.

Acceleration (a) =
$= \frac{v - u}{t} = \frac{70 - 0}{ \frac{1}{3} } \\ \\ = 70 \times 3 = 210 \: \: km \: \: hr ^{ - 2}$
Now,

Distance travelled (S) = ut +½× at²

= 0 + ½× 210 ×⅓×⅓

= 35/3 km = 11.66km

Distance in next 20 mins=vt +½ × at²

= 70× ⅓ + ½×210×⅓×⅓

= 70/3 + 35/3

= 105/3 = 35 km

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